((x^3-1)/(x^2-4))*((2x-4)/(x^2-2x+1))

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Solution for ((x^3-1)/(x^2-4))*((2x-4)/(x^2-2x+1)) equation: 


D( x )

x^2-4 = 0

x^2-(2*x)+1 = 0

x^2-4 = 0

x^2-4 = 0

1*x^2 = 4 // : 1

x^2 = 4

x^2 = 4 // ^ 1/2

abs(x) = 2

x = 2 or x = -2

x^2-(2*x)+1 = 0

x^2-(2*x)+1 = 0

x^2-2*x+1 = 0

x^2-2*x+1 = 0

DELTA = (-2)^2-(1*1*4)

DELTA = 0

x = 2/(1*2)

x = 1 or x = 1

x in (-oo:-2) U (-2:1) U (1:2) U (2:+oo)

((x^3-1)/(x^2-4))*((2*x-4)/(x^2-(2*x)+1)) = 0

((x^3-1)/(x^2-4))*((2*x-4)/(x^2-2*x+1)) = 0

((x^3-1)*(2*x-4))/((x^2-4)*(x^2-2*x+1)) = 0

x^2-2*x+1 = 0

x^2-2*x+1 = 0

DELTA = (-2)^2-(1*1*4)

DELTA = 0

x = 2/(1*2)

x = 1 or x = 1

(x-1)^2 = 0

((x^3-1)*(2*x-4))/((x^2-4)*(x-1)^2) = 0

( 2*x-4 )

2*x-4 = 0 // + 4

2*x = 4 // : 2

x = 4/2

x = 2

( x^3-1 )

1*x^3 = 1 // : 1

x^3 = 1

x^3 = 1 // ^ 1/3

x = 1

x in { 2} 

x in { 1} 

x belongs to the empty set

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